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4.9x^2+340x-1360=0
a = 4.9; b = 340; c = -1360;
Δ = b2-4ac
Δ = 3402-4·4.9·(-1360)
Δ = 142256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{142256}=\sqrt{16*8891}=\sqrt{16}*\sqrt{8891}=4\sqrt{8891}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(340)-4\sqrt{8891}}{2*4.9}=\frac{-340-4\sqrt{8891}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(340)+4\sqrt{8891}}{2*4.9}=\frac{-340+4\sqrt{8891}}{9.8} $
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